Defined in header <math.h> | ||
|---|---|---|
float expm1f( float arg ); | (1) | (since C99) |
double expm1( double arg ); | (2) | (since C99) |
long double expm1l( long double arg ); | (3) | (since C99) |
Defined in header <tgmath.h> | ||
#define expm1( arg ) | (4) | (since C99) |
2.7182818) raised to the given power arg, minus 1.0. This function is more accurate than the expression exp(arg)-1.0 if arg is close to zero.arg has type long double, expm1l is called. Otherwise, if arg has integer type or the type double, expm1 is called. Otherwise, expm1f is called.| arg | - | floating point value |
If no errors occur earg-1 is returned.
If a range error due to overflow occurs, +HUGE_VAL, +HUGE_VALF, or +HUGE_VALL is returned.
If a range error occurs due to underflow, the correct result (after rounding) is returned.
Errors are reported as specified in math_errhandling.
If the implementation supports IEEE floating-point arithmetic (IEC 60559),
The functions expm1 and log1p are useful for financial calculations, for example, when calculating small daily interest rates: (1+x)n-1 can be expressed as expm1(n * log1p(x)). These functions also simplify writing accurate inverse hyperbolic functions.
For IEEE-compatible type double, overflow is guaranteed if 709.8 < arg.
#include <stdio.h>
#include <math.h>
#include <float.h>
#include <errno.h>
#include <fenv.h>
// #pragma STDC FENV_ACCESS ON
int main(void)
{
printf("expm1(1) = %f\n", expm1(1));
printf("Interest earned in 2 days on $100, compounded daily at 1%%\n"
" on a 30/360 calendar = %f\n",
100*expm1(2*log1p(0.01/360)));
printf("exp(1e-16)-1 = %g, but expm1(1e-16) = %g\n",
exp(1e-16)-1, expm1(1e-16));
// special values
printf("expm1(-0) = %f\n", expm1(-0.0));
printf("expm1(-Inf) = %f\n", expm1(-INFINITY));
//error handling
errno = 0; feclearexcept(FE_ALL_EXCEPT);
printf("expm1(710) = %f\n", expm1(710));
if(errno == ERANGE) perror(" errno == ERANGE");
if(fetestexcept(FE_OVERFLOW)) puts(" FE_OVERFLOW raised");
}Possible output:
expm1(1) = 1.718282
Interest earned in 2 days on $100, compounded daily at 1%
on a 30/360 calendar = 0.005556
exp(1e-16)-1 = 0, but expm1(1e-16) = 1e-16
expm1(-0) = -0.000000
expm1(-Inf) = -1.000000
expm1(710) = inf
errno == ERANGE: Result too large
FE_OVERFLOW raised|
(C99)(C99) | computes e raised to the given power (\({\small e^x}\)ex) (function) |
|
(C99)(C99)(C99) | computes 2 raised to the given power (\({\small 2^x}\)2x) (function) |
|
(C99)(C99)(C99) | computes natural (base-e) logarithm of 1 plus the given number (\({\small \ln{(1+x)} }\)ln(1+x)) (function) |
C++ documentation for expm1 |
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