Defined in header <math.h> | ||
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#define isfinite(arg) /* implementation defined */ | (since C99) |
Determines if the given floating point number arg has finite value i.e. it is normal, subnormal or zero, but not infinite or NaN. The macro returns an integral value.
FLT_EVAL_METHOD is ignored: even if the argument is evaluated with more range and precision than its type, it is first converted to its semantic type, and the classification is based on that.
| arg | - | floating point value |
Nonzero integral value if arg has finite value, 0 otherwise.
#include <stdio.h>
#include <math.h>
#include <float.h>
int main(void)
{
printf("isfinite(NAN) = %d\n", isfinite(NAN));
printf("isfinite(INFINITY) = %d\n", isfinite(INFINITY));
printf("isfinite(0.0) = %d\n", isfinite(0.0));
printf("isfinite(DBL_MIN/2.0) = %d\n", isfinite(DBL_MIN/2.0));
printf("isfinite(1.0) = %d\n", isfinite(1.0));
printf("isfinite(exp(800)) = %d\n", isfinite(exp(800)));
}Possible output:
isfinite(NAN) = 0 isfinite(INFINITY) = 0 isfinite(0.0) = 1 isfinite(DBL_MIN/2.0) = 1 isfinite(1.0) = 1 isfinite(exp(800)) = 0
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(C99) | classifies the given floating-point value (function macro) |
|
(C99) | checks if the given number is infinite (function macro) |
|
(C99) | checks if the given number is NaN (function macro) |
|
(C99) | checks if the given number is normal (function macro) |
C++ documentation for isfinite |
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